x^2+3x=5(x+3)-16

Solution for x^2+3x=5(x+3)-16 equation:

x^2+3x=5(x+3)-16

We move all terms to the left:

x^2+3x-(5(x+3)-16)=0


We calculate terms in parentheses: -(5(x+3)-16), so:

5(x+3)-16

We multiply parentheses

5x+15-16

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)


We get rid of parentheses

x^2+3x-5x+1=0

We add all the numbers together, and all the variables

x^2-2x+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{2}=1$